The perimeter of an isosceles trapezoid circumscribed around a circle is 44.

The perimeter of an isosceles trapezoid circumscribed around a circle is 44. Find the area of the trapezoid if the radius of the circle is 5.

Since a circle is inscribed in the trapezoid, the sum of the lengths of the bases of the trapezoid is equal to the sum of the lengths of its lateral sides.

AB + CD = BC + AD = Ravsd / 2 = 44/2 = 22 cm.

The height BH of the trapezoid is equal to the diameter of the inscribed circle. BH = 2 * R = 2 * 5 = 10 cm.

Determine the area of the trapezoid.

Savsd = (BC + AD) * BН / 2 = 22 * 10/2 = 110 cm2.

Answer: The area of the trapezoid is 110 cm2.



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