The perimeter of an isosceles trapezoid is 150 cm, and the lateral side is 30 cm. Find the middle line of the trapezoid.

Since in an isosceles trapezoid, the sides are 30 cm, and the perimeter is 150 cm, then:

BC + AD = P – (AB + CD);

ВС + АD = 150 – (30 + 30) = 150 – 60 = 90 cm.

m = 90/2 = 45 cm.

Answer: The middle line of the trapezoid is 45 cm.



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