The perimeter of an isosceles triangle is 10 cm and the difference between its 2 sides is 2 cm Find the sides AB BC AC

ABC is an isosceles triangle and its two sides are equal to: AB = BC.

Let the length of the side AB be equal to “x” cm.

Then the length of the BC side is also equal to “x” cm, and the length of the CA side is equal to “x – 2” cm.

The perimeter of a triangle “P” is the sum of the lengths of all its sides.

Knowing that the perimeter of this triangle is 10 cm, we will compose the equation:

x + x + (x – 2) = 10;

3x – 2 = 10;

3x = 10 + 2;

3x = 12;

x = 12: 3;

x = 4 (cm) length of sides AB and BC.

1) x – 2 = 4 – 2 = 2 (cm) length of the CA side.

Answer: AB = 4 cm, BC = 4 cm, CA = 2 cm.