The perimeter of an isosceles triangle is 14 cm. The difference between the two sides is 3.2 cm.

The perimeter of an isosceles triangle is 14 cm. The difference between the two sides is 3.2 cm. Find the length of the sides of the triangle.

1. A, B, C – the vertices of the triangle.

2. According to the condition of the problem, one of the sides is 3.2 cm larger than the other. Let’s say AC = AB + 3.2 cm.

3. Further calculations are performed using the formula for calculating the perimeter:

AC + AB + BC = 14 cm.

BC = AB, since the triangle is isosceles.

4. Substitute in the original expression AB instead of BC and (AB + 3,2) instead of AC:

2AB + AB + 3.2 = 14 cm.

3AB = 10.8 cm.

AB = 10.8: 3 = 3.6 cm.

AC = 3.6 + 3.2 = 6.8 cm.

Answer: BC = AB = 3.6 cm, AC = 6.8 cm