The perimeter of an isosceles triangle is 24 cm; its base is 2 cm larger than the lateral side.

The perimeter of an isosceles triangle is 24 cm; its base is 2 cm larger than the lateral side. Find the sides of the triangle.

The perimeter of a triangle is equal to the sum of the lengths of all its sides.
Since the triangle is isosceles, its sides are equal.
Let’s designate them with the letter A.
Then the base of the triangle is (A + 2) cm.
Therefore, the perimeter can be written as P = A + A + (A + 2) = 24 cm.
3 * A + 2 = 24.
3 * A = 22.
A = 22/3 = 7 (1/3) cm.
The base of the triangle is 7 (1/3) + 2 = 9 (1/3) cm.
Thus, the sides of the triangle are 7 (1/3) cm and the base is 9 (1/3) cm.