The perimeter of an isosceles triangle is 25 cm. The length of the longest side is 9 cm. Find the lengths of the other sides.

Suppose the largest side of a triangle is its base.

In this case, the other two sides will be the hips of the triangle, which are the same length.

Determine the sum of their lengths.

For this perimeter, subtract 9 cm.

25 – 9 = 16 cm.

From this it follows that the length of the other two sides will be equal:

16/2 = 8 cm.

Let’s say the side of the triangle is 9 cm.

Since the triangle is isosceles, the length of the second side will also be 9 cm.

9 + 9 = 18 cm (the sum of the sides).

The length of the base will be:

25 – 18 = 7 cm.

Answer: 9, 8 and 8 cm or 9, 9 and 7 cm.



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