The perimeter of an isosceles triangle is 3.4 dm and the lateral side is 1 dm larger. Find all sides of this triangle.

It is known from the condition that the perimeter of an isosceles triangle is 3.4 dm, and the lateral side is 1 dm larger than the base. We need to find all the sides of this triangle.

To do this, we will compose and solve the equation. Let’s start by recalling the formula for calculating the perimeter of a triangle:

P = a + b + c;

P = 2a + b for an isosceles triangle, since the sides of an isosceles triangle are equal.

The base will be denoted by x dm, then the side is (x + 1) dm.

We solve the equation:

2 (x + 1) + x = 3.4;

2x + 2 + x = 3.4;

2x + x = 3.4 – 2;

3x = 1.4;

x = 1.4: 3;

x = 0.4 (6) dm is the length of the base of the triangle, and (0.4 (6) + 1) = 1.4 (6) dm is the side.