The perimeter of an isosceles triangle is 50 cm, and its base is half the size of the lateral side. Find the sides of the triangle

Given:
isosceles triangle ABC,
AB and BC lateral sides,
AC base,
AB = BC,
AB = 2 * AC.
P ABC = 50 centimeters.
Find the lengths of the sides of the triangle: AC, AB, BC -?
Solution:
The perimeter of the triangle ABC is:
P ABC = AC + AB + BC;
R ABC = AC + 2 * AC + 2 * AC;
50 = AC * (1 + 2 + 2);
50 = AC * (3 + 2);
50 = AC * 5;
AC = 50: 5;
AC = 10 centimeters;
AB = BC = 2 * 10 = 20 centimeters.
Answer: 10 centimeters; 20 centimeters; 20 centimeters.