The perimeter of an isosceles triangle is 50 cm, and one of its sides is 9 cm larger than the other, find the sides of the triangle.

Let the length of the base be x centimeters, then the lengths of the sides are (x + 9) centimeters. We know that the perimeter of this isosceles triangle is 50 centimeters. Let’s make the equation:

x + x + 9 + x + 9 = 50;

x + x + x + 18 = 50;

x + x + x = 50 – 18;

x + x + x = 32;

x * (1 + 1 + 1) = 32;

x * 3 = 32 (in order to find an unknown factor, you need to divide the product by a known factor);

x = 32: 3;

x = 10 2/3 centimeters – base;

10 2/3 + 9 = 19 2/3 centimeters – sides.

Answer: 19 2/3 centimeters; 19 2/3 centimeters; 10 2/3 centimeters.