The perimeter of an isosceles triangle is 50 cm. One side is 13 cm larger than the other. Find the sides of the triangle.

1) Triangle ABC-p / b
Next AB = BC (according to sv-wu)
AC-base
2) the perimeter of the triangle ABC = 50cm
(AB + BC + AC = 50)
Let x cm – side of the speaker
Then (x + 13) – side AB and BC
knowing that the perimeter of the p / b triangle is 50 cm, we compose and solve the equation
X + 13 + x + 13 + x = 50
3x = 24
x = 8
8 cm – speaker base
3) 8 + 13 = 21 (cm) – sides AB and BC
Answer: AB = 21 cm; BC = 21 cm; AC = 8 cm