The perimeter of an isosceles triangle is 50cm. One of its sides is 13cm larger than the other.
| August 1, 2021 | education
The perimeter of an isosceles triangle is 50cm. One of its sides is 13cm larger than the other. Find the sides of the triangle.
1. A, B, C – the vertices of the triangle.
2. According to the condition of the problem, one of the sides is 13 cm larger than the other. Let’s say AC = AB – 13 cm.
3. Further calculations are performed using the formula for calculating the perimeter:
AC + BC + AB = 50 cm.
BC = AB, since the triangle is isosceles.
4. Substitute in the original expression AB instead of BC and (AB – 13) instead of AC:
AB – 13 + 2AB = 50 cm.
3AB = 63 cm.
AB = 63: 3 = 21 cm.
AC = 21 – 13 = 8 cm.
Answer: AC = 8 cm, BC = AB = 21 cm.
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