The perimeter of an isosceles triangle MNK is 56 in. If the length of the base MN is equal to 18.4 dm, then the lateral

| May 7, 2021 | education

The perimeter of an isosceles triangle MNK is 56 in. If the length of the base MN is equal to 18.4 dm, then the lateral sides will be divided into segments of which length by the medians drawn to them.

The perimeter of an isosceles triangle can be found by summing the length of its base and side, multiplied by two. For this triangle, you can write the following expression:

p = MN + 2NK.

Let us find from this expression the length of its lateral side:

2NK = p – MN;

NK = (p – MN) / 2.

Let’s convert all numerical values ​​to centimeters. Each decimeter has 10 centimeters, so let’s multiply them by 10:

56 dm = 560 cm;

18.4 dm = 184 cm.

Substitute the numeric parameters into the expression for finding the side:

NK = (560 – 184) / 2 = 376/2 = 188 cm.

Medians are segments that divide the opposite side in two, therefore we divide the length of the side by 2:

188: 2 = 94 cm.

Answer: the medians will divide the sides by 94 cm.



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