The perimeter of rectangle ABCD is 28 and the diagonal of AC is 10 Find the perimeter of triangle ABC.

Draw a rectangle ABCD, mark the sides, for example AB = a, BC = b.

РABCD = (a + b) * 2 = 28, therefore, a + b = 28: 2 = 14.

Build a diagonal AC, designate c, c = 10 (by condition). You have received the ABC triangle.

PABC = a + b + c = 14 + 10 = 24.

Answer: PABC = 24.



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