The perimeter of the ABC triangle is 132cm. The sum of the sides AB and BC is 79cm

The perimeter of the ABC triangle is 132cm. The sum of the sides AB and BC is 79cm, which is 11cm less than the sum of the sides AC and BC. Find the lengths of the sides of the triangle?

1. Find the side of the AC, reducing the length of all sides of the triangle by the sum of the lengths AB and BC:
132 – 79 = 53 cm.
2. Let’s find the sum of AC and BC, if it is more than the sum of AB and BC by 11 cm:
11 + 79 = 90 cm.
3. Find the side of the BC by subtracting the length of the AC from the sum of AC and BC:
90 – 53 = 37 cm.
4. Let’s find what AB is equal to, decreasing the length of all sides of the triangle by the sum of AC and BC:
132 – (37 + 53) = 132 – 90 = 42 cm.
Answer: AB is 42 cm, BC is 37 cm, AC is 53 cm.