The perimeter of the ABC triangle is 60 cm. The AB side is 5 cm larger than the AC side, and the BC

The perimeter of the ABC triangle is 60 cm. The AB side is 5 cm larger than the AC side, and the BC side is larger than the AB side 5 cm. Find the sides of the triangle

The first side of the triangle is AB = AC + 5 cm.
The second side of the triangle is BC = AB + 5 cm or AC + 5 + 5 = AC + 10.
Third side of triangle AC.
As you know, the perimeter of a triangle is the sum of all sides, and is calculated by the following formula: P = AB + BC + AC.
Substitute all the known values of the sides of the triangle in the formula and find the perimeter: 60 = AC + 5 + AC + 10 + AC = 3AC + 15.
60 – 15 = 3AC.
45 = 3AC.
AC = 45/3 = 15 cm.
Answer: The AC side is 15 cm.
BC = AC + 10 = 15 + 10 = 25 cm.
Answer: the side of the BC is 25 cm.
AB = AC + 5 = 15 + 5 = 20 cm.
Answer: side AB is 20 cm.



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