The perimeter of the ABC triangle is 88cm. sides AB and BC are equal.

The perimeter of the ABC triangle is 88cm. sides AB and BC are equal. And the length of the AC side is 32cm. which are equal to the lengths of the sides AB and BC.

Given:

triangle ABC, AB = BC, AC = 32 cm, P = 88 cm.

Solution :

The perimeter of a triangle is the sum of all its sides, that is:

AB + BC + AC.

Let the side AB be x cm, then BC is also equal to x cm (since the sides are equal). By the condition of the problem, it is known that AC = 32 cm and the perimeter is 88 cm.

Let’s make the equation:

x + x + 32 = 88,

2 * x = 88 – 32,

2 * x = 56,

x = 56: 2,

x = 28 cm – side AB.

Therefore, the side of the BC is also 28 cm.

Answer: AB = BC = 28 cm.