The perimeter of the base of a regular quadrangular pyramid is 12 cm. Find the total surface area

The perimeter of the base of a regular quadrangular pyramid is 12 cm. Find the total surface area of the pyramid if its apothem is 5 cm.

If the perimeter is p = 12 cm, then the side of the square at the base of the pyramid is b = p / 4 = 12/4 = 3 cm.

Side area of the pyramid:

Sb = pa / 2, where a is apothem.

Base area:

Sо = b ^ 2.

Full area S:

S = Sb + So = pa / 2 + b ^ 2 = (12 * 5) / 2 + 3 ^ 2 = 39 cm ^ 2.

Answer: 39 cm ^ 2.



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