The perimeter of the BCA triangle is 480 dm, one of its sides is 150 dm

The perimeter of the BCA triangle is 480 dm, one of its sides is 150 dm. Calculate the other two sides of the triangle if their difference is 90 dm.

It is known from the condition that the perimeter of the BCA triangle is 480 dm, one of its sides is 150 dm. It is also known that the difference between the other two sides is 90 dm.

In order to find what the sides of the triangle are equal to, we compose and solve a linear equation.

Let us denote by the variable x one of the unknown sides, then the second side is equal to (x + 90).

The perimeter of a triangle is the sum of the lengths of all sides of the triangle.

P = a + b + c;

150 + x + x + 90 = 480;

2x = 480 – 150 – 90;

2x = 240;

x = 120 dm second side, 120 + 90 = 210 dm.