The perimeter of the EFTQ parallelogram is 60 cm. F = 150 ° and the perpendicular FM is 5 cm.
The perimeter of the EFTQ parallelogram is 60 cm. F = 150 ° and the perpendicular FM is 5 cm. Find the sides of the parallelogram.
A parallelogram is a quadrilateral in which the opposite sides are parallel, that is, lie on parallel lines.
Consider the triangle EFM in the parallelogram EFTQ: angle F = 150 degrees, then you can find the angle E, it will be equal to 180 – 150 = 30 degrees.
Since FM is perpendicular, the angle M = 90 degrees. According to the assignment, FM = 5 cm, and the found angle is E = 30 degrees. The side that lies opposite the 30 degree angle will be half the hypotenuse. Therefore, you can find the side of EF, which is 2 * FM = 2 * 5 = 10.
The perimeter of the parallelogram is 60 cm, which means EF + FT + TQ + EQ = 60.
60 – 10 – 10 = TQ + EQ;
40 = TQ + EQ;
Since TQ = EQ, they will be equal to 40/2 = 20 cm.
Answer: the sides will be 10 cm and 20 cm.