The perimeter of the first square is 5 times the perimeter of the second square.

The perimeter of the first square is 5 times the perimeter of the second square. Find the area of the second square if its perimeter is 200 cm less than the first.

It is known that the perimeter of a square is equal to the product of the side length by 4.

Find the length of the side 2 of the square:

1) Let’s denote the side of the 2 square as a, the perimeter of 2 of the square P, then the perimeter of 1 of the square is 5P.

2) 5P – P = 200;

4P = 200;

P = 50;

3) a = 50/4 = 12.5.

Find the area of 2 squares (S):

S = a ^ 2;

S = (12.5) ^ 2 = 156.25 cm ^ 2.

Answer: 156.25 cm ^ 2.