The perimeter of the parallelogram is 100 degrees, one of the sides

The perimeter of the parallelogram is 100 degrees, one of the sides of the parallelogram is 8 more than the other. Find the smaller side of the parallelogram.

Determine the sum of the degrees of two adjacent sides.

To do this, we divide the perimeter of the parallelogram into 2 equal parts, since the sums of opposite angles are equal to each other.

Will be:

100/2 = 50.

Let’s denote the smaller side as x.

Since the second is 8 degrees larger, it will be: x + 8.

We get the equation.

x + x + 8 = 50.

2 * x = 50 – 8.

2 * x = 42.

x = 42/2 = 21.

Answer:

The smaller side of the parallelogram is 21.