The perimeter of the quadrangle is 52cm. One side of it is equal to 1dm 4cm, the second is 5cm less than

| September 23, 2021 | education

The perimeter of the quadrangle is 52cm. One side of it is equal to 1dm 4cm, the second is 5cm less than the first, and the third is 8cm more than the second. Find the length of the fourth side.

The perimeter is the sum of all the sides of the polygon, in this case the quadrilateral.
In order to find the second side of this quadrilateral, you need to subtract 5 cm from the first known one (by condition, the second side is 5 cm less than the first).
First, you need to translate the length of the first side to centimeters.
We get: 1 dm 4 cm = 10 cm + 4 cm = 14 cm.
14 – 5 = 9 cm – second side.
In order to find the third side, you need to add 8 cm to the second (according to the condition, the third side is 8 cm larger than the second).
We get: 9 + 8 = 17 cm.
We need to find the fourth side. Let’s designate it as X. We are also given a perimeter equal to 52 cm.
We get: 14 + 9 + 17 + X = 52.
From here we find X:
X = 52 – 14 – 9 – 17 = 12 cm.
Answer: 12 cm.



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