The perimeter of the rectangle ABCD is 40 dm. The length of the rectangle is 12 cm. Find the width of the rectangle.

Knowing that the perimeter of the rectangle is equal to the sum of all four of its sides, we introduce the unknown “x”, denoting the length of the width of the rectangle, and form an equation with one unknown. Since the two sides of the rectangle (length and width) are pairwise equal to each other, we can make the equation: 2 (X + 12) = 40. Hence, X + 12 = 20 or X = 8 centimeters.
Answer: The width of the rectangle is 8 centimeters.



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