The perimeter of the rectangle is 10dm. The length is equal to three point seven sixteenths of an inch.

The perimeter of the rectangle is 10dm. The length is equal to three point seven sixteenths of an inch. Find the width of the rectangle.

A rectangle is a rectangle whose opposite sides are equal and the corners are right.

The perimeter is the sum of all sides. For such a figure, it is determined by the formula:

P = 2a + 2b. Provided that this value is 10 dm, and the length = 3 7/16 (represented as an improper fraction 55/16), we express the width:

2b = 10 – 2 * 55/16. = 10 – 55/8. Let’s bring to a common denominator:

2b = 80/8 – 55/8 = 25/8. We must divide this value by the first factor, but when dividing fractions, we flip the divisor and perform multiplication:

b = 25/8 * 1/2 = 25/16 = 1 9/16 dm – width.