The perimeter of the rectangle is 11.2 dm. The length of this rectangle is 2.5 times greater than its width.

The perimeter of the rectangle is 11.2 dm. The length of this rectangle is 2.5 times greater than its width. Find the area of the rectangle.

It is known from the condition that the perimeter of the rectangle is 11.2 dm. The length of this rectangle is 2.5 times greater than its width. In order to find the area of a rectangle, we first need to find the lengths of its sides.

Let us denote one of the sides of the rectangle using the variable x, then the second side can be written as 2.5x, compose and solve the equation.

The perimeter of the rectangle is:

P = 2 (a + b);

2 (x + 2.5x) = 11.2;

3.5x = 5.6;

x = 1.6 in. on the smaller side, 1.6 * 2.5 = 4 in. on the larger side.

S = a * b = 1.6 * 4 = 6.4 dm2.