The perimeter of the rectangle is 11.2 in. The length of this rectangle is 2.5 times the width

The perimeter of the rectangle is 11.2 in. The length of this rectangle is 2.5 times the width, find the area of the rectangle.

Let’s say the width of the rectangle is x dm.

It is known that the length is 2.5 times the width, which means the length is 2.5 * x dm.

Since the perimeter of the rectangle is 11.2 dm, we compose the equation:

2 * (x + 2.5 x) = 11.2,

3.5 * x = 5.6,

x = 5.6: 3.5,

x = 1.6 (dm).

If the width of the rectangle is 1.6 dm, then its length is:

1.6 * 2.5 = 4 (dm).

Knowing the length and width of the rectangle, we can calculate its area:

S = 1.6 * 4 = 6.4 dm².

Answer: S = 6.4 dm².