The perimeter of the rectangle is 114 dm, and its width is 9 dm less than the length. Find the sides of the rectangle.

Let us express the width of the rectangle through a, then the length will be equal to a + 9. Let’s make the equation:

(a + (a + 9)) * 2 = 114;

(a + a + 9) * 2 = 114;

2a + 9 = 114: 2;

2a + 9 = 57;

2a = 57 – 9;

2a = 48;

a = 48: 2;

a = 24 dm – the width of the rectangle.

Let’s find the length of the rectangle:

24 + 9 = 33 dm – the length of the rectangle.

Answer: the width of the rectangle is 24 dm, the length of the rectangle is 33 dm.