The perimeter of the rectangle is 12.8 cm and one of its sides is 2.4 cm smaller than the other.

The perimeter of the rectangle is 12.8 cm and one of its sides is 2.4 cm smaller than the other. Find the area of the triangle.

Given:
The perimeter of the rectangle is 12.8 centimeters.
One side of the figure is 2.4 centimeters smaller than the other.

Let one side of the quadrangle be x centimeters.
Then the length of the second side will be (x + 2.4) centimeters.
Let’s make the equation:
x + x + x + 2.4 + x + 2.4 = 12.8;
4x = 12.8 – 4.8;
4x = 8;
x = 8: 4;
x = 2;
The first side is 2 centimeters long.
Let’s calculate the length of the second:
2 + 2.4 = 4.4 cm.
Find the area of the rectangle:
S = 2 * 4.4 = 8.8 cm2.
Answer: 8.8 cm2.



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