The perimeter of the rectangle is 120 cm. The length of the rectangle is 10 cm longer than the width. Find the area.

To solve this problem, remember that the perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. Let the width be – x cm, then the length is equal to – x + 10 cm. Knowing that the perimeter is 120 cm, we will compose the equation.

2 * (x + x + 10) = 120;

4x + 20 = 120;

4x = 120 – 20;

4x = 100;

x = 100/4;

x = 25 cm.

Width 25 cm, length 25 + 10 = 35 cm. The area of a rectangle is equal to the product of length and width. S = a * b, where a is the length and b is the width.

S = 25 * 35 = 875 sq. Cm.

Answer: 875 sq. Cm.