# The perimeter of the rectangle is 150 dm. Its length is 150 cm greater than its width.

**The perimeter of the rectangle is 150 dm. Its length is 150 cm greater than its width. Calculate the lengths of the sides of the rectangle.**

Let’s make an equation according to the condition of the task, and find what the sides of the rectangle are equal to. If its perimeter = 150 dm, and the length is 150 cm greater than the width (15 dm, since 1 dm = 10 cm).

P = 2a + 2b.

Substitute the known values, (denote the smallest side as “x”):

2 * (x + 15) + 2x = 150.

Let’s expand the brackets:

2x + 30 + 2x = 150.

Let’s perform actions with the coefficients of the variable on the left side of the equation, and transfer the number to the right, while the sign in front of it changes to the opposite.

4x = 150 – 30 = 120.

x = 120: 4 = 30.

Therefore, width = 30 dm, length = 30 + 15 = 45 dm. Which corresponds to 300 and 450 cm.