The perimeter of the rectangle is 16 4/9 dm, its width is 4 1/2 dm. Find the area of the rectangle.

The perimeter of the rectangle is P = ½ * (a + b), where a and b are the sides of the rectangle.

Side a = 4 ½ dm. Let’s find the second side.

16 [4/9] = ½ * (4 ½ + b);

148/9 * 2 = 4 ½ + b;

b = 296/9 – 4 ½;

b = 32 [8/9] – 4 ½;

b = 32 [16/18] – 4 [9/18];

b = 28 [7/18] dm;

the area of the rectangle is s = a * b;

s = 4 ½ * 28 [7/18];

s = 9/2 * 511/18;

s = 127.75 dm2.