The perimeter of the rectangle is 160 cm. The length of the rectangle is nine-sevenths of its width.

The perimeter of the rectangle is 160 cm. The length of the rectangle is nine-sevenths of its width. Find the area of the rectangle.

1. Take the width of the rectangle in s. Then its length is equal to 9s / 7. Adding the length and width and multiplying this sum by 2, we get a perimeter of 160 cm.Solve the resulting equation:

(s + 9s / 7) * 2 = 160,

2 * 16s / 7 = 160,

32s / 7 = 160,

32s = 7 * 160,

32s = 1120,

c = 1120/32,

c = 35.

2. Find the length of the rectangle:

9 * 35/7 = 9 * 5 = 45 cm.

3. Find the product of length and width, we get the area of the rectangle:

45 cm * 35 cm = 1575 cm2.

Answer: the area of the rectangle is 1575 cm2.