The perimeter of the rectangle is 18m, and one of its sides is 2.5m larger than the other.

The perimeter of the rectangle is 18m, and one of its sides is 2.5m larger than the other. Find the ratio of the length of the rectangle to its width.

Find the sum of the two sides (length and width) of the rectangle.

Divide the specified perimeter value by 2.

18/2 = 9 meters.

Let’s designate one of the sides as a m.

Since the second side is 2.5 meters larger, it will be: a + 2.5.

We get the equation:

a + a + 2.5 = 9.

2 * a = 9 – 2.5.

2 * a = 6.5.

a = 6.5 / 2 = 3.25 m (width).

3.25 + 2.5 = 5.75 m (length).

Find the ratio of the length of the rectangle to its width.

We divide 5.75 m by 3.25 m.

5.75 / 3.25 = 1 250/325 = 1 10/13.

Answer:

The length is 1 x 10/13 times greater than the width.