The perimeter of the rectangle is 20 cm and one side is three tenths of the perimeter.

The perimeter of the rectangle is 20 cm and one side is three tenths of the perimeter. Find the lengths of the sides of the rectangle.

The perimeter of any rectangle is twice the sum of its two sides.

P = 2 * (a + b).

The length of one of the sides (for example, side a) of the rectangle specified in the problem statement is 3/10 * 20 = 6 (cm).

Substitute the known perimeter of the rectangle and the length of the found side into the equation above. Then we solve this equation.

20 = 2 * (6 + b).

20/2 = 6 + b.

10 = 6 + b.

b = 10 – 6.

b = 4 (cm) – the length of the second side of the rectangle.

Answer: the lengths of the sides of this rectangle are 6 cm and 4 cm.



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