The perimeter of the rectangle is 24 cm, one side is 1.4 cm larger than the other

| April 26, 2021 | education

The perimeter of the rectangle is 24 cm, one side is 1.4 cm larger than the other. Determine the distances from the point of intersection of the diagonals to the sides of the rectangle.

Let’s say that the length of one side of the rectangle is x cm.

Since the second side is 1.4 cm larger than the first, its length will be: x + 1.4 cm.

We find the sum of the two sides.

To do this, divide the perimeter into 2 equal parts.

24/2 = 12 cm.

The sum of the parties will be:

x + x + 1.4 = 12.

2 * x = 12 – 1.4 = 10.6 cm.

x = 10.6 / 2 = 5.3 cm (rectangle width).

x + 1.4 = 5.3 + 1.4 = 6.7 cm (rectangle length).

The point of intersection of the diagonals is in the center of the figure, so the distance to the sides will be:

5.3 / 2 = 2.65 cm.

6.7 / 2 = 3.35 cm.

Answer:

2.65 cm and 3.35 cm.



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