The perimeter of the rectangle is 28cm, its length is 10cm, find the perimeter

The perimeter of the rectangle is 28cm, its length is 10cm, find the perimeter and the square of the square, the side of which is equal to the width of the rectangle.

Let us determine the width of this rectangle, denoting it as x, knowing that, by definition, the perimeter of a rectangle is equal to twice the sum of its length and its width:

2 (10 + x) = 28;

10 + x = 14;

x = 4.

Let’s define the perimeter of a square, the side of which is equal to the width of the specified rectangle:

4 + 4 + 4 + 4 = 4 * 4 = 16.

Determine the area of a square whose side is equal to the width of the specified rectangle:

4 * 4 = 16.

Answer: The perimeter of the resulting square is 16 meters, and its area is 16 m2.