The perimeter of the rectangle is 30 cm. Its length is 11 cm. Find the perimeter and area of the square whose

The perimeter of the rectangle is 30 cm. Its length is 11 cm. Find the perimeter and area of the square whose side is equal to the width of the rectangle. Solve the problem in detail.

Let us express the width of the rectangle, provided that its perimeter = 30 cm and the length is 11 cm from the formula:
P = 2a + 2b.

Therefore: b = (P – 2a): 2 = (30 – 2 * 11): 2 = (30 – 22): 2 = 8: 2 = 4 cm.

In a square, all sides are equal, each is 4 cm, the sum of all four is calculated by the formula:
P = 4a = 4 * 4 = 16 cm.

Square:
S = a² = 4² = 16 cm².