The perimeter of the rectangle is 32 dm. What is its area if its length is 7 times its width?

univerkov | August 4, 2021 | education

Let the width of the rectangle be X. Then the length of the rectangle is 7 * X. Let us express the perimeter of rectangle P in terms of X. P = X + 7 * X + X + 7 * X = 16 * X.
Solve the equation 16 * X = 32. X = 2.
Thus, the width of the rectangle is 2 inches and the length is 14 inches. The area of a rectangle S is equal to the product of its length and width. S = 14 * 2 = 28 sq. Dm.
Answer: 28 sq. Dm.

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