The perimeter of the rectangle is 32cm. Its width is 6cm shorter than its length. Find the sides of the rectangle

It is known from the condition that the perimeter of the rectangle is 32 cm. It is also known that its width is 6 cm shorter than the length. In order to find the sides of the rectangle, we compose and solve the equation.

Let’s denote the length of the rectangle using the variable x cm, then the width can be denoted as (x – 6) cm.

Perimeter of the rectangle:

P = 2 (a + b);

2 (x + x – 6) = 32;

2x – 6 = 16;

2x = 16 + 6;

2x = 32;

x = 32: 2;

x = 16 cm is the length of the rectangle, then the width of the rectangle is 16 – 6 = 10 cm.

Answer: 16 cm; 10 cm.



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