The perimeter of the rectangle is 34 cm, one side is 3 cm larger than the other. Calculate the area of the rectangle.

Let one side of the rectangle be x, then since the second side is 3 cm larger than the first, then the second side is equal to 3 + x. The perimeter of a rectangle is equal to the sum of all its sides. Since the opposite sides of the rectangle are equal, then P = 2 * a + 2 * b = 2 * x + 2 * (3 + x) = 2x + 6 + 2x = 4x + 6. By the condition of the problem, the perimeter of the rectangle is 34 cm: 34 = 4x + 6.4x = 34 – 6.4x = 28, x = 28: 4, x = 7 cm. One side of the rectangle is 7 cm, and the second is 7 + 3 = 10 cm. The area of the rectangle is equal to the product of length and width: S = a * b, S = 7 * 10 = 70 sq. Cm. Answer: the area of the rectangle is 70 sq. Cm.