The perimeter of the rectangle is 4 m 8 dm, one of its sides is 5 times larger than the adjacent side.

According to the condition of this task, we will compose an equation and find the sides of the rectangle. We know that the perimeter is 4 m 8 dm (48 dm), one side is 5 times larger than the other.

The formula for calculating the sum of all sides of such a figure is as follows:

P = 2a + 2b.

Substitute the known values:

2 * 5x + 2x = 48.

On the left side of the equation, we will perform actions with the coefficients of the variable, and transfer the known number to the right, while changing the sign in front of it to the opposite.

12x = 48.

To find the second factor, you need to divide the product by the first.

x = 48: 12 = 4.

Therefore, width = 4 dm, length = 5 * 4 = 20 dm.



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