The perimeter of the rectangle is 40.2 m, and its length is 2.3 m longer than the width. Find the area of the rectangle.

1) Let x m be the width of the rectangle.

2) Then (x + 2.3) m is its length.

3) (2x + 2 * (x + 2.3)) m is the perimeter of a given rectangle, which, according to the condition of the problem, is 40.2 m.Therefore, we write the equality:

2x + 2 * (x + 2.3) = 40.2.

4) Solve the equation and find the value of x:

2x + 2x + 4.6 = 40.2;

4x + 4.6 = 40.2;

4x = 40.2 – 4.6;

4x = 35.6;

x = 35.6: 4;

x = 8.9.

5) We find that x = 8.9 m – the width of the rectangle.

6) Let’s calculate its length:

8.9 + 2.3 = 11.2 m.

7) Calculate the area of this rectangle:

11.2 * 8.9 = 99.68 m ^ 2.

Answer: 99.68 m ^ 2.