The perimeter of the rectangle is 40dm, and the width is 4cm less than the length. How many square decimeters is the area of a rectangle less than the area of a square with the same perimeter?
Ppr = 40dm
L – the length of the rectangle
H = L-0.4 – rectangle width
Sq = (Ppr / 4) ^ 2 = 100 dm2
Spr = L * (L-0,4)
Ppr = 2 * L + 2 * (L-0.4) = 4L-0.8
40 = 4L-0.8
4L = 40.8
L = 10.2 dm
Spr = L * (L-0.4) = 10.2 * (10.2-0.4) = 10.2 * 9.8 = 99.96 dm2
Sq-Spr = 100 dm2-99.96 dm2 = 0.04 dm2 – the difference between the required areas
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