The perimeter of the rectangle is 42 cm. The ratio of its length to width is 4: 3. Find the area of the rectangle.

To solve this problem, you first need to determine the sum of the length and width of the rectangle.

To do this, divide the specified perimeter of the figure into 2 equal parts.

We get:

42 2 = 21 cm.

We find the sum of the ratios of length and side.

3 + 4 = 7.

From this it follows that the length is 4/7 of 21 cm and the width is 3/7 of 21 cm.

We express the length and width in centimeters.

We multiply 21 cm by the found parts.

21 * 4/7 = 3 * 4 = 12 cm (length).

21 * 3/7 = 3 * 3 = 9 cm (width).

The area will be equal to:

12 * 9 = 108 cm2