# The perimeter of the rectangle is 44 1/2 cm and the width is 10 1/2 cm, find the area of the rectangle.

August 29, 2021 | education

| By the condition of the problem, the perimeter of the rectangle is 44 1/2 cm, as well as its width is 10 1/2 cm, we find the length of the rectangle:

a = P / 2 – b, where a is the length of the rectangle, P is the perimeter of the rectangle, b is the width of the rectangle.

a = 44 1/2: 2 – 10 1/2;

a = 44.5: 2 – 10.5;

a = 22.25 – 10.5;

a = 11.75 (cm) – the length of the rectangle.

In order to find the area of a rectangle, you need to find the product of width and length:

S = a * b, where S is the area of the rectangle, a is the length of the rectangle, b is the width of the rectangle.

S = 11.75 * 10.5;)

S = 123.375 (cm2)

Answer: 123.375 cm2