The perimeter of the rectangle is 44.2 in. Its length is 2.4 times greater than its width. Find the area of the rectangle.

First of all, we will determine, by making an equation, to which the sides of the rectangle are equal, provided that one is 2.4 times larger than the other, and the perimeter is 44.2 dm.

Let’s remember the formula for calculating the sum of all sides of such a figure:

P = 2a + 2b.

Hence:

2x + 2 * (2.4x) = 44.2.

Let’s perform actions with the coefficients of the variable on the left side of the equation:

6.8x = 44.2.

To find the second factor, divide the product by the first:

x = 44.2: 6.8 = 6.5.

Therefore, width = 6.5 dm and length = 2.4 * 6.5 = 15.6 dm.