The perimeter of the rectangle is 48 cm, and its length is 2 cm more than the width. Find the area of this rectangle?

Given:
The perimeter P of the rectangle is 48 centimeters.
The length is 2 centimeters longer than its width.
Let the width of the quadrangle be x centimeters.
Then the length of this figure will be equal to (x + 2) centimeters.
Let’s make the equation:
x + x + x + 2 + x + 2 = 48;
4x = 48 – 4;
4x = 44;
x = 44: 4;
x = 11.
The rectangle is 11 centimeters wide.
Let’s calculate its length:
11 + 2 = 13 centimeters.
We calculate the area of the figure using the formula S = a * b:
S = a * b = 13 * 11 = 143 cm2.
Answer: the area of the rectangle is 143 cm2.