The perimeter of the rectangle is 48 cm. Find the area of the rectangle if its width is 3 times less than its length.

To solve this problem, recall the formula for the area of ​​a rectangle. The area of ​​the rectangle is equal to the product of the length and the width. S = a * b, where a is the length and b is the width. The perimeter of a rectangle is the sum of the lengths of all its sides. Since in a rectangle the opposite sides are equal, then P = 2 * (a + b), where a is the length, b is the width. Let the width of the rectangle be -x, then the length of the rectangle is 3x. Knowing that the perimeter is 48 cm, we create an equation.
2 * (x + 3x) = 48;
2x + 6x = 48;
8x = 48;
x = 48/8;
x = 6.
The width is 6 cm, the length is 6 * 3 = 18 cm. Let’s calculate the area.
S = 6 * 18 = 108 sq. Cm.
Answer: 108 sq. Cm.