The perimeter of the rectangle is 50 cm. The length of the rectangle is 15 cm longer than the width.

The perimeter of the rectangle is 50 cm. The length of the rectangle is 15 cm longer than the width. Find the area of the rectangle.

Let’s denote the width of the rectangle through x, then the length of the rectangle will be: (x + 15).

Let’s make an equation for the perimeter of the rectangle and solve it:

2 * (x + 15) + 2 * x = 50;

2x + 30 + 2x = 50;

4x = 50 – 30;

4x = 20;

x = 20/4;

x = 5 cm.

Knowing the width of the rectangle, we can find its length: 5 + 15 = 20 cm.

Then the area of the rectangle will be equal to the product of length and width:

20 * 5 = 100 cm2.

Answer: the area of the rectangle is 100 cm2.