The perimeter of the rectangle is 54cm. Its length is 5cm longer than its width. Find the area of the rectangle.

Let x be the value of the width of the rectangle, then since the length is 5 cm greater than the width, then the value of the length is: x + 5. The perimeter of the rectangle is equal to the sum of all its sides, and since the rectangle has opposite sides, then P = 2 * a + 2 * b … Substituting our values for the perimeter and sides, we get the equation: 54 = 2 * x + 2 * (x + 5), 54 = 2x + 2x + 10, 4x = 54 – 10, 4x = 44, x = 44: 4, x = 11 cm.The width of the rectangle is 11 cm, and the length is: 11 cm + 5 cm = 16 cm.The area of the rectangle is: S = a * b = 16 cm * 11 cm = 176 cm square.